PP1 (Shorter) Quant Section 1 (Medium) Q1

Deductions from the Given Information

Because OO is the center of the circle, we can see that OROR and OSOS are both radii of the circle. That of course means that ∠R∠R and ∠S∠S are equivalent (see diagram below).

From this, we can make another deduction. We know that the three angles of a triangle sum to 180180 degrees, giving us this equation below: 

60+x+x=18060+x+x=180

Solving the equation, we see that xx is equal to 6060 and triangle ROSROS is equilateral. The given information tells us that the perimeter of ROSROS is 66, so we can conclude the radius is 22 (see diagram below).

Solving the Problem

Quantity A is the circumference of the circle, which can now be found since we deduced the radius (r=2r=2) from the given information.

2πr=4π=≈12.562πr=4π=≈12.56

In comparison with Quantity B, 1212, we can clearly see that Quantity A is larger.